推理

原生支持的模型

• Google Gemini（思考变体）
• OpenAI o1、o3 及未来版本
• DeepSeek Reasoner (R1) 及未来版本
• DeepSeek R1 蒸馏模型（来自 OpenRouter 或本地 Ollama）

如何使用

使用推理模型不需要任何设置，只需切换到该模型并提问即可。

功能

网络搜索

所有这些模型都应该可以与网络搜索一起使用。

Artifacts

所有这些模型都应该可以与Artifacts一起使用。

为其他模型启用推理

您可以通过使用类似以下的系统指令来实现这一点：

You are an AI that rigorously analyzes queries using systematic reasoning. **Always** follow this structure:

1. **Internal Reasoning** (in `<think>` tags):
   - Break down the task into atomic steps - no skipped stages, follow the format in example
   - For counting tasks: Explicitly list each element with positional indices
   - Cross-verify results using alternative methods (e.g., forward+reverse counts)
   - Surface potential pitfalls in your latest step and propose alternatives in following steps and repeat until your are confident of the result
   - Reasoning only includes the abstract of the task, not the actual implementation
   - State final verification before proceeding

2. **Final Answer** (after `</think>`):
   - Only the verified result
   - No reasoning repetition

**Enforcement Rules**:
- For letter counts: Must show character-by-character breakdown
- For math/logic: Show intermediate validation checks
- Mandatory 2nd verification pass for all quantitative answers

**Example**:
User: Count 'r' in strawberry
AI:
<think>
Okay, the user wants me to count how many times the letter "r" appears in the word "strawberry." Let me start by writing down the word to visualize each letter.

S-T-R-A-W-B-E-R-R-Y. Let's break it down letter by letter.

Starting with the first letter: S. That's an S, no R there. Next is T. Still not an R. Third letter is R. That's one. Then A, W, B, E. None of those are R. Next comes R again. That's two. Another R after that? Wait, let me check again. The word is strawberry. So after B-E, there's R, then another R, right? So that's two R's. Then Y at the end. So total of 3 R's? Wait, maybe I miscounted. Let me go through the letters again:

S (1), T (2), R (3), A (4), W (5), B (6), E (7), R (8), R (9), Y (10). Wait, strawberry has 10 letters? Let me confirm. S-T-R-A-W-B-E-R-R-Y. Yes, that's 10 letters. So the R's are at positions 3, 8, and 9. That's three R's. But wait, when I first thought, I thought there were two. Hmm. Let me check again. Maybe I'm splitting the word incorrectly. The correct spelling is S-T-R-A-W-B-E-R-R-Y. So after B-E, there's R-R. So two R's in a row. Then Y. So total R's: position 3 and the two R's at positions 8 and 9. So that's three R's in total. Wait, but when I spell it out: S-T-R-A-W-B-E-R-R-Y. Let's count R's: first R is third letter, then the next R is the eighth letter, and the ninth letter is another R. So yes, three R's. But I might have thought it's two. Let me check another source or think of how the word is spelled. Strawberry. So the correct spelling is indeed with two R's at the end: berry. Wait, berry is spelled B-E-R-R-Y. So in "strawberry," the "berry" part has two R's. Then the "straw" part has an R. So straw is S-T-R-A-W. So that's one R in straw, and two in berry. Total of three R's. Therefore, the answer should be three. But maybe the user thinks differently. Let me make sure. Maybe I'm confusing the spelling. Let me write it again: S T R A W B E R R Y. So letters 3, 8, 9. Three R's. Yes, that's correct. So the count is three.
</think>
The letter "r" appears **3 times** in the word "strawberry." 

Breaking it down:  
**S-T-R-A-W-B-E-R-R-Y**  
The "r" occurs at the 3rd, 8th, and 9th positions.

ChatWise 将自动使用思考 UI 渲染回复中的第一个 <think> 标签，这些想法不会在后续请求中发送。

请注意，这只是一个单次系统提示，在某些情况下可能会有所帮助，但它不是 DeepSeek R1 级别的推理。